Julian Prein
bbf9a1da58
Setting LC_ALL=C makes it possible to use the range `[0-?]` instead of splitting it into `[0-9:-?]` as done previously. Without LC_ALL, sed complains with: sed: -e expression #1, char 21: Invalid range end The GNU manual explains this partially, although I still don't quite understand why this range specifically does not work in `en_US.utf8`. See: > Within a bracket expression, a *range expression* consists of two > characters separated by a hyphen. It matches any single character that > sorts between the two characters, inclusive. In the default C locale, > the sorting sequence is the native character order; for example, > `[a-d]` is equivalent to `[abcd]`. Link: https://www.gnu.org/software/sed/manual/sed.html#Character-Classes-and-Bracket-Expressions
9 lines
217 B
Bash
Executable File
9 lines
217 B
Bash
Executable File
#!/bin/sh
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# SPDX-License-Identifier: MIT
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# Copyright (c) 2025 Julian Prein
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#
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# Remove ANSI SGR (Select Graphic Rendition) escape sequences, e.g. setting
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# color or bold font.
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env LC_ALL=C sed 's/\[[0-?]*[ -/]*m//g'
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